Calculate mass and area moment of inertia for common shapes: cylinder, sphere, rod, rectangle, I-beam, circle, and more. Includes parallel axis theorem.
The Moment of Inertia Calculator computes both mass moment of inertia (for rotational dynamics) and area moment of inertia (for beam bending analysis) for common geometric shapes. Select from solid and hollow cylinders, spheres, rods, rectangles, circles, I-beams, and T-sections. That makes it useful when the same project mixes rotating parts and structural members.
Mass moment of inertia (I = Σmr²) determines how much torque is needed to angularly accelerate an object — the rotational analog of mass. A flywheel with high moment of inertia resists speed changes, while a figure skater pulls arms in to reduce I and spin faster.
Area moment of inertia (second moment of area) determines beam stiffness and strength. An I-beam's shape concentrates material far from the neutral axis, maximizing I for minimum weight — which is why I-beams support heavy loads efficiently. Use the calculator to compare how the same material behaves when you change the shape, the axis, or the offset from the centroid.
Use this calculator when you need a quick inertia value for a common shape without opening a handbook or rebuilding the formula from scratch. It is useful for beam checks, rotating-part estimates, and comparing how shape changes stiffness or rotational response. That makes it practical for both mechanical and structural work.
Solid Cylinder (about axis): I = ½mr². Sphere: I = ⅖mr². Thin Rod (center): I = (1/12)mL². Rectangle Area: I = bh³/12. Circle Area: I = πr⁴/4. Parallel Axis: I = I_cm + md² (or I = I₀ + Ad² for area).
Result: I = 0.200 kg·m²
A solid cylinder of mass 10 kg and radius 0.2 m rotating about its axis: I = ½ × 10 × 0.2² = ½ × 10 × 0.04 = 0.200 kg·m². The radius of gyration k = √(I/m) = 0.141 m.
Newton's second law for rotation is τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration. Just as F = ma governs linear motion, this governs rotation. The moment of inertia depends on both the total mass and how it's distributed relative to the rotation axis.
Practical applications include flywheel design (maximize I for energy storage), motor sizing (I determines acceleration time), vehicle wheel design (lower I = faster acceleration), and figure skating physics (reducing I by pulling arms in increases spin rate by conservation of angular momentum).
The area moment of inertia (often called just "I" in structural contexts) appears in the beam bending formula σ = My/I and the deflection formula δ = PL³/(48EI). Engineers select beam cross-sections to provide adequate I for the expected loads, while minimizing material weight.
Standard structural shapes (W-beams, channels, angles, tubes) have tabulated I values in steel and aluminum design manuals. For custom cross-sections, I is calculated by dividing the shape into simple parts, computing each part's I about the neutral axis using the parallel axis theorem, and summing.
The parallel axis theorem is perhaps the most important tool for computing moments of inertia of complex shapes. It states that I about any axis equals I about the parallel axis through the centroid plus the product of mass (or area) and the square of the offset distance. This allows decomposition of complex shapes into simple components.
For mass: I measures resistance to angular acceleration (I = Σmr²). For area: I (second moment of area) measures resistance to bending. Both depend on how mass or area is distributed relative to the rotation/bending axis.
It lets you find the moment of inertia about any axis parallel to one through the center of mass: I = I_cm + md² (mass) or I = I₀ + Ad² (area). d is the distance between axes. This always increases I.
I-beams concentrate material in the flanges, far from the neutral axis. Since area moment of inertia weights area by distance² from the axis, material farther away contributes much more to stiffness. An I-beam can be 10× stiffer than a solid rectangle of the same weight.
k = √(I/m) for mass, or k = √(I/A) for area. It's the distance from the axis at which all the mass or area could be concentrated to give the same moment of inertia. It's used in buckling calculations for columns.
S = I/c, where c is the distance from the neutral axis to the outermost fiber. Section modulus directly relates to bending stress: σ = M/S. Larger S means lower stress for the same bending moment.
Yes, critically. A rod has very different I about its end vs its center. A cylinder has different I about its axis vs perpendicular to it. Always specify the rotation/bending axis.