Compute partial sums of arithmetic, geometric, telescoping, p-series, and power sum series with convergence analysis and visualization.
Series — the sum of terms of a sequence — are central to calculus, analysis, and applied mathematics. Whether you're adding the first 100 natural numbers, computing compound interest totals, or testing whether an infinite sum converges, understanding partial sums and convergence is essential.
This calculator handles five major series types: arithmetic series (constant differences), geometric series (constant ratios), p-series (Σ 1/nᵖ, including the famous Basel problem), telescoping series (Σ 1/(n(n+1))), and power sums (Σ nᵏ for sum of squares, cubes, etc.). For each type, it computes partial sums, evaluates closed-form expressions where available, and determines convergence.
The visualization shows how partial sums approach their limit (for convergent series) or grow without bound (for divergent ones). The detailed table provides term-by-term breakdowns so you can see exactly how each term contributes to the total. Closed-form formulas — like Gauss's n(n+1)/2 for natural numbers, or the geometric sum formula a(1−rⁿ)/(1−r) — are computed alongside the numerical sum for verification. This tool is invaluable for calculus students, engineers computing series solutions, and anyone working with sequences and summation.
Series computations involve repetitive summation that becomes impractical for large n, and determining convergence requires comparing series against known benchmarks. This calculator handles five major series types with closed-form evaluation, convergence testing, and convergence-limit error analysis — all in one tool. The step-by-step partial sums table and convergence visualization show exactly how each term contributes and how quickly (or slowly) the series approaches its limit, which is essential for calculus coursework and engineering series solutions.
Arithmetic: Sₙ = n/2·(2a₁ + (n−1)d) Geometric: Sₙ = a₁(1−rⁿ)/(1−r) p-series: Σ 1/nᵖ converges iff p > 1 Telescoping: Σ 1/(n(n+1)) = 1 − 1/(n+1)
Result: S₁₀₀ = 5,050
Sum of 1+2+3+…+100 = 100·101/2 = 5050 (Gauss's formula).
A series converges if its partial sums approach a finite limit and diverges otherwise. Geometric series converge when |r| < 1 (limit a₁/(1−r)), while all arithmetic series with d ≠ 0 diverge. p-series Σ 1/nᵖ converge if and only if p > 1, making the boundary case p = 1 (the harmonic series) a famous divergent series. Telescoping series collapse because consecutive terms cancel, always leaving a finite difference. Understanding these convergence criteria is the gateway to Taylor series, Fourier series, and power series solutions in differential equations.
Some of the most celebrated results in mathematics are series evaluations. Gauss showed Σk = n(n+1)/2 as a child. Euler proved the Basel problem: Σ 1/n² = π²/6. The Leibniz formula gives π/4 = 1 − 1/3 + 1/5 − 1/7 + …. The sum of cubes Σk³ = [n(n+1)/2]² (Nicomachus' theorem) reveals that the sum of the first n cubes equals the square of the sum of the first n integers. These identities connect elementary summation to deep results in analysis and number theory. Faulhaber's formulas generalize power sums Σnᵏ to polynomial closed forms for every positive integer k.
Engineers use series constantly: Taylor expansions approximate nonlinear systems, Fourier series decompose periodic signals into frequency components, and power series solve ordinary differential equations. In physics, perturbation theory expresses solutions as series in a small parameter, and partition functions in statistical mechanics are infinite sums over energy states. Even the compound interest formula is a geometric series application. Understanding when a series converges (and how fast) determines whether a calculation is practical and how many terms are needed for a given precision.
The sum of the first n terms of a series: Sₙ = a₁ + a₂ + … + aₙ. Use this as a practical reminder before finalizing the result.
When the partial sums approach a finite limit as n → ∞. Otherwise it diverges.
Finding Σ 1/n² = π²/6. Euler solved this in 1734, proving the sum is exactly π²/6 ≈ 1.6449.
A series where consecutive terms cancel, leaving only the first and last. Σ 1/(n(n+1)) = 1/(n) − 1/(n+1).
Identify the pattern: constant difference → arithmetic, constant ratio → geometric, 1/nᵖ → p-series, cancellation → telescoping. Keep this note short and outcome-focused for reuse.
Yes — the harmonic series 1 + 1/2 + 1/3 + … has terms approaching 0 but diverges. The terms must decrease fast enough.