Demonstrate the triangle proportionality theorem — a line parallel to one side of a triangle divides the other two sides proportionally. Enter triangle sides and a dividing line position to verify...
The **Triangle Proportionality Theorem** (also called the Basic Proportionality Theorem or Side Splitter Theorem) is a foundational result in Euclidean geometry. It states that if a line is drawn parallel to one side of a triangle, intersecting the other two sides, then it divides those two sides proportionally.
More formally, given triangle ABC with a line DE parallel to side BC that intersects side AB at D and side AC at E, the theorem guarantees that **AD/DB = AE/EC**. This elegant relationship lies at the heart of similarity theory and is widely used in surveying, architecture, computer graphics, and engineering design.
This calculator lets you input the three sides of a triangle and specify where a parallel dividing line crosses one of the sides. It then computes both segments on each divided side, verifies the proportional relationship, and displays the ratio. You can also explore the converse — if a line divides two sides proportionally, then it must be parallel to the third side.
Use the presets to explore classic configurations such as the midsegment (ratio 1 : 1), the golden-section cut, and various integer-proportion cases. The reference table summarizes key related theorems so you can see how the proportionality theorem connects to the broader landscape of triangle geometry.
The triangle proportionality theorem is easy to state but surprisingly easy to misapply when you are tracking several segments at once. One wrong correspondence between AB and AC, or one mistaken ratio direction, can spoil the entire setup. This calculator keeps the segment relationships aligned so you can test a parallel-line construction without re-deriving every length manually.
It is particularly helpful when teaching or studying similarity. Because it shows the split on both sides of the triangle and the resulting parallel segment DE, it makes the connection between proportional division and similar triangles much easier to see than a static textbook diagram.
If DE ∥ BC in △ABC with D on AB and E on AC, then AD / DB = AE / EC. Equivalently, AD / AB = AE / AC. Segment DE = BC × (AD / AB).
Result: DB = 6, AE = 3.2, EC = 4.8, DE = 4.8, and AD/DB = AE/EC = 2/3
Triangle ABC has AB = 10, BC = 12, CA = 8. A line parallel to BC meets AB at D where AD = 4, so DB = 6. Then AE / EC = 4 / 6 = 2/3, giving AE = 3.2 and EC = 4.8. The parallel segment DE = 12 × (4/10) = 4.8.
The core reason the theorem works is similarity. Once DE is parallel to BC, the smaller triangle ADE and the larger triangle ABC share corresponding angles, so every matching side scales by the same factor. The familiar ratio AD/DB = AE/EC is just one visible consequence of that similarity structure.
Many textbook problems use the midsegment as the cleanest example because the ratio becomes 1:1 and the parallel segment is half the third side. More advanced exercises choose uneven splits such as 2:3 or 3:1 to force you to distinguish between part-to-part ratios like AD/DB and part-to-whole ratios like AD/AB. Confusing those two is one of the most common mistakes in this topic.
When solving proportionality problems, label the full sides first, then the segments, and only then form the ratio. Check whether the problem is asking for a piece-to-piece relationship or a smaller-to-larger triangle scale factor. If the same value appears in both segment ratios and the computed DE agrees with the similarity factor, your setup is probably correct.
It states that a line drawn parallel to one side of a triangle divides the other two sides in equal ratios. If DE ∥ BC in △ABC, then AD/DB = AE/EC.
Yes. The Basic Proportionality Theorem (BPT) and the Side Splitter Theorem are alternate names for the same result.
Yes. The converse states that if a line divides two sides of a triangle proportionally, then it is parallel to the third side.
The midsegment connects the midpoints of two sides (ratio 1:1). It is parallel to the third side and exactly half its length.
Absolutely. The proportionality holds for any real-valued side lengths, including irrational ones.
The parallel line creates a smaller triangle similar to the original. All corresponding-side ratios equal AD/AB, and the area ratio equals (AD/AB)².