Convert between standard and general forms of a sphere equation. Enter center and radius or general-form coefficients to get both equations, center, radius, volume, and surface area.
The equation of a sphere in three-dimensional space describes the set of all points (x, y, z) at a fixed distance r from a center point (h, k, l). In standard form this is (x − h)² + (y − k)² + (z − l)² = r². Expanding the squares yields the general form: x² + y² + z² + Dx + Ey + Fz + G = 0, where D = −2h, E = −2k, F = −2l, and G = h² + k² + l² − r².
Converting between these two representations is a common task in analytic geometry, multivariable calculus, and computer graphics. The standard form immediately reveals the center and radius, while the general form is useful when fitting a sphere to data points or when simplifying algebraic manipulations.
This calculator supports both directions: enter the center coordinates and radius to generate both equation forms, or enter the general-form coefficients D, E, F, G to extract the center and radius. It also computes the sphere's volume and surface area for quick reference.
Use the tool for homework problems that ask you to rewrite a sphere equation, for verifying completing-the-square work in 3D, or for any analytical geometry task involving spheres.
This calculator is useful when you need to move quickly between the geometric view of a sphere and the algebraic view of its equation. In homework and exam prep, that usually means checking whether a completed-square result really corresponds to the intended center and radius. In applied settings, it helps when a sphere is described by coefficients from a model, measurement fit, or simulation output and you need the physical center, radius, volume, or surface area immediately.
It is also helpful for spotting invalid equations early. If the coefficient form does not produce a positive radius squared, the expression does not represent a real sphere. That makes this tool practical not just for solving problems, but for verifying whether a proposed sphere equation is mathematically meaningful.
Standard form: (x − h)² + (y − k)² + (z − l)² = r² General form: x² + y² + z² + Dx + Ey + Fz + G = 0 Center from general: (−D/2, −E/2, −F/2) Radius from general: r = √(D²/4 + E²/4 + F²/4 − G) Volume: (4/3)πr³ Surface Area: 4πr²
Result: Standard form: (x − 3)² + (y − 4)² + (z − 5)² = 36; general form: x² + y² + z² − 6x − 8y − 10z + 14 = 0.
Entering h = 3, k = 4, l = 5, and radius = 6 gives r² = 36. The general-form coefficients become D = -2h = -6, E = -2k = -8, and F = -2l = -10. The constant term is G = h² + k² + l² − r² = 9 + 16 + 25 − 36 = 14, so the converted equation is x² + y² + z² − 6x − 8y − 10z + 14 = 0.
The biggest advantage of standard form is that it tells you the sphere's geometry immediately. Once the equation is written as (x − h)² + (y − k)² + (z − l)² = r², you can read the center and radius directly without any extra interpretation. That makes standard form ideal for graphing, identifying intercept behavior, and visualizing how the sphere sits in three-dimensional space.
General form is often the version that appears after expansion, substitution, or model fitting. In analytic geometry, you may start with a condition involving several points and end up with x² + y² + z² + Dx + Ey + Fz + G = 0. In that setting, the coefficients carry the same information as the center and radius, but it is hidden until you complete the square or use the coefficient relationships. Being able to move between the two forms is what turns a messy algebra expression into a clear geometric object.
Many errors come from sign handling. Because D = -2h, E = -2k, and F = -2l, a negative coefficient in general form usually means a positive center coordinate. Another common mistake is forgetting to check whether D²/4 + E²/4 + F²/4 − G is positive. If it is zero or negative, the equation does not describe a real sphere with positive radius. Using a calculator to confirm both the conversion and the radius check is a reliable way to catch those mistakes before they affect the rest of the problem.
The standard form is (x − h)² + (y − k)² + (z − l)² = r², where (h, k, l) is the center and r is the radius. Use this as a practical reminder before finalizing the result.
Complete the square for each variable. The center is (−D/2, −E/2, −F/2) and the radius is √(D²/4 + E²/4 + F²/4 − G).
Then the equation has no real solution — the set of points is empty and does not represent a sphere. Keep this note short and outcome-focused for reuse.
A circle in 2D uses (x − h)² + (y − k)² = r². A sphere extends this to 3D by adding a z-term. The conversion process is identical.
Yes, but you need a system of four equations. Substitute each point into the general form to get four linear equations in D, E, F, G, then solve.
If the coefficient is not 1, divide the entire equation by that coefficient first. The standard derivation assumes each squared term has coefficient 1.